Answer:
[tex]\boxed{\sf \ \ \ 3x^3-9x^2-30x=3x(x-5)(x+2) \ \ \ }[/tex]
Step-by-step explanation:
hello
step 1 - put 3x in factor
[tex]3x^3-9x^2-30x=3x(x^2-3x-10)[/tex]
step 2 - factorise the quadratic form
product of zeros are -10 and the sum is 3, the roots are 5 and -2, as below
[tex]x^2-3x-10=x^2+2x-5x-10=x(x+2)-5(x+2)=(x-5)(x+2)[/tex]
so the answer is
[tex]3x^3-9x^2-30x=3x(x-5)(x+2)[/tex]
hope this helps
