Answer:
[tex]\boxed{\sf \ \ (x+1)^2-9=0 \ \ }[/tex]
Step-by-step explanation:
hello,
we can notice that
[tex](x+1)^2=x^2+2x+1[/tex]
so
[tex]x^2+2x=(x+1)^2-1[/tex]
and then
[tex]x^2+2x-8=0\\<=> (x+1)^2-1-8=0\\\\<=> (x+1)^2=9\\<=> x+1=3 \ or \ x+1=-3\\<=> x=2 \ or \ x=-4\\[/tex]
solutions are 2 and -4
hope this helps
