Answer:
1) 67.35 H202 x [tex]\frac{2H2O}{2H2O2}[/tex]
The H2O2's cancel out, and we have 67.35.
2) Br2+Cl2=2BrCl
3) 2.74 Cl2= 2BrCl/Cl2
Thus, we have 2.74(2) which is 5.48
Explanation:
1) 67.35 H202 x [tex]\frac{2H2O}{2H2O2}[/tex]
The H2O2's cancel out, and we have 67.35.
2) Br2+Cl2=2BrCl
3) 2.74 Cl2= 2BrCl/Cl2
Thus, we have 2.74(2) which is 5.48
