Sytrisse Sytrisse
  • 12-06-2020
  • Mathematics
contestada

What is the vertical asymptote for the reciprocal of y=8x-4

Respuesta :

wifilethbridge wifilethbridge
  • 19-06-2020

Answer:

The vertical asymptote for the reciprocal of y=8x-4 is [tex]\frac{1}{2}[/tex]

Step-by-step explanation:

Given Equation : [tex]y = 8x-4[/tex]

Reciprocal of given equation =[tex]\frac{1}{y}=\frac{1}{8x-4}[/tex]

Now to find the vertical asymptote

[tex]\frac{1}{y}=\frac{1}{8x-4}[/tex]

Equate denominator to 0

8x-4=0

8x=4

[tex]x=\frac{4}{8}[/tex]

[tex]x=\frac{1}{2}[/tex]

So, The vertical asymptote is[tex]\frac{1}{2}[/tex]

Hence the vertical asymptote for the reciprocal of y=8x-4 is [tex]\frac{1}{2}[/tex]

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