Michaelyork7382 Michaelyork7382
  • 12-06-2020
  • Chemistry
contestada

The half life of iodine-125 is 60 days. What fraction of 125I nuclides would be left after 360 days?

Respuesta :

emmartunde emmartunde
  • 16-06-2020

Answer:

THE FRACTION OF IODINE-125 REMAINING AFTER 360 DAYS IS 1/64.

Explanation:

half life of iodine- 125 = 60 days

Time elapsed for a decay = 360 days

using the formula:

                            Nt = No (1/2)^t/t1/2

The fraction left after a decay will be represented as:

Nt / No = (1/2) ^t/t1/2

Nt / No = (1/2) ^ 360 /60

Nt / No = (1/2) ^6

Nt / No = 1 / 64

The fraction of iodine-125 (Nt / No) remaining after 360 days is 1/ 64.

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