brirhodes
brirhodes brirhodes
  • 14-05-2020
  • Mathematics
contestada

Solve 4(x-1)^2 + 2 = 38.

Solve 4x12 2 38 class=

Respuesta :

wegnerkolmp2741o
wegnerkolmp2741o wegnerkolmp2741o
  • 14-05-2020

Answer:

x = -2, 4

Step-by-step explanation:

4(x-1)^2 + 2 = 38

Subtract 2 from each side

4(x-1)^2 + 2-2 = 38-2

4(x-1)^2  = 36

Divide each side by 4

4/4(x-1)^2  = 36/4

(x-1)^2  = 9

Take the square root of each side

sqrt((x-1)^2 ) =±sqrt( 9)

x-1 =

Add 1 to each side

x-1 +1= 1 ±3

x = 1 ±3

x = 1+3 = 4

   1 - 3 = -2

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kdefee9255
kdefee9255 kdefee9255
  • 14-05-2020

X=-2,4

Just took the test the answer is correct

Answer Link

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