13-05-2020
Mathematics

contestada

What is the center of the circle?
(x + 1)2 + (y – 12 = 256

Respuesta :

nktselepov nktselepov

13-05-2020

The equation of circle:

[tex](x-x_0)^2+(y-y_0)^2=r^2[/tex]

[tex](x + 1)^2 + (y - 1)^2 = 256[/tex]

so, the center of the circle is (-1; 1)

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