Answer: 16.1 g/mol
Explanation:
P - the pressure of the gas
V - the volume it occupies
n - the number of moles of gas
V= 1.0L
P= 1atm
T=273.15k
PV= nRt
n=[tex]\frac{PV}{RT}[/tex]
=[tex]\frac{(1atm)(1.0L)}{(0.0821\frac{L*atm}{molk} )(273.15K)}[/tex]
n=0.04459mol
Molar mass: [tex]\frac{grams}{mol}[/tex]
= [tex]\frac{0.716g}{0.04459 mol}[/tex]
Molar mass: 16.1 g/mol
