Answer:
The answer is "SAS".
Step-by-step explanation:
In this question we assume two angle is given that are:
[tex]\ Two \ triangles \angle ABD \ and \angleDCA \\\\\ In \ this \ on \ angle \ is \ common \ that \ is, \\\\ AD=AD \\\\AB= CD \\\\\angle A \ is \ equal \ = \angle A \ (\ which \ is \ given)\\\\[/tex]
That's why SAS rule is correct.
