[tex] \frac{x + 4}{ x^{2} + 5x + 6 } [/tex] + [tex] \frac{x + 3}{ x^{2} - 16} [/tex] Factor the denominator terms
[tex] \frac{(x + 4)(x + 3)}{(x + 3)(x + 2)(x + 4)(x - 4)} [/tex] (x + 4) and (x + 3) will cancel out
[tex] \frac{1}{(x + 2)(x - 4)} [/tex] Here's the final answer.
