Suppose a triangle has sides a, b, and c let theta be the angle opposite the side of length a. If cos theta < 0 what must be true? a- b^2+c^2>a^2. b- a^2+b^2=c^2. c- b^2+c^2c^2
Using the cosine rule, a² = b² + c² -2 bc cos θSImplifying the equation in terms of cos theta, cos(θ) = (a² + c² - b²)/(2bc) (a² + c² - b²)/(2bc) > 0 a² + c² - b² > 0 assuming b and c are non zeros, the resulting inequality should be a² + c² > b²
