Answer:
0%
Explanation:
Normal female genotype = [tex]X^HX^H[/tex]
Genotype of a man with hemophilia = [tex]X^hY[/tex]
Crossing the two in marriage:
[tex]X^HX^H[/tex] x [tex]X^hY[/tex]
Progeny: [tex]X^HX^h, X^HY, X^HX^h, and X^HY[/tex]
The two sons from the cross have the genotype [tex]X^HY[/tex] and are therefore free from hemophilia.
Hence, the percentage of their sons that will have hemophilia is zero (0).
