Answer: Option C) 6
Explanation:
2C2H6(g) + 7O2(g) ---> 4CO2(g) + 6H2O(g)
The equation above shows the combustion of ethane, C2H6 in oxygen, O2 to yield carbon dioxide, CO2 and water, H2O.
The mole ratio on combustion are as follows:
2 mole of C2H6 produce 4 mole of CO2
3 mole of C2H6 produce Z mole of CO2
To get the value of Z, cross multiply
Z x 2 mole = 3 mole x 4 mole
2Z = 12
Divide both sides by 2
2Z/2 = 12/2
Z = 6 moles
Thus, in the combustion of ethane, 6 moles of CO2 can be produced from 3.00 mole of C2H6
