The modified area is (1/48) (2πr(4h+3r))
Step-by-step explanation:
Let the radius be 'r' and height be 'h'.
Area of cylinder= 2π r(h+r)
The radius is shrunk down to quarter of its original radius
r = r/4
The height is reduced to a third of its original height
h = h/3
New Area = 2π(r/4) [(h/3) +(r/4) ]
= (1/4)2πr[(4h+3r) /12]
= (1/48) (2πr(4h+3r))
