tianamfarmer
tianamfarmer
14-07-2016
Mathematics
contestada
evaluate
9C5
and
11P4
.
Respuesta :
konrad509
konrad509
14-07-2016
[tex]9C5=\dfrac{9!}{5!4!}=\dfrac{6\cdot7\cdot8\cdot9}{2\cdot3\cdot4}=6\cdot7\cdot3=126\\\\ 11P4=\dfrac{11!}{7!}=8\cdot9\cdot10\cdot11=7920[/tex]
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