Answer: It will become,
[tex]49t^6-4k^4=(7t^3-2k^4)(7t^3+2k^4)[/tex]
Step-by-step explanation:
Since we have given that
[tex]49t^6-4k^8[/tex]
We need to factorise the above expression:
[tex]49t^6-4k^8\\\\=(7^2(t^2)^3-2^2(k^2)^4\\\\=(7t^3)^2-(2k^4)^2[/tex]
So, we can apply the identity :
[tex]a^2-b^2=(a+b)(a-b)[/tex]
Here,
[tex]a=7t^3\\\\b=2k^4[/tex]
so, it will become,
[tex]49t^6-4k^4=(7t^3-2k^4)(7t^3+2k^4)[/tex]
