EndothermiCat
EndothermiCat EndothermiCat
  • 11-07-2016
  • Mathematics
contestada

Find the approximate surface-area-to-volume ratio of a bowling ball with a radius of 5 inches

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Edufirst
Edufirst Edufirst
  • 21-07-2016
surface area = 4π(r^2) = 4π(5)^2

Volume = [4/3]π(r^3) = [4/3]π(5^3)

ratio = 4π(5)^2 / [4/3]π(5^3) = 3/5 = 0.6
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