Answer:
[tex]\frac{x-2}{2(x+2)}[/tex]
Step-by-step explanation:
Given
[tex]\frac{4x}{x+2}[/tex] × [tex]\frac{x-2}{8x}[/tex]
Cancel 4x and 8x on the numerator/ denominator, thus
[tex]\frac{1}{x+2}[/tex] × [tex]\frac{x-2}{2}[/tex]
= [tex]\frac{x-2}{2(x+2)}[/tex]
