Answer:
[tex]\large\boxed{\large\boxed{x=54\º}}[/tex]
Explanation:
In the figure, two secants that intersect outside a circle form an angle with measure of xº and the measures of the arcs formed are 136º and 28º.
When two secants intersect outside a circle, the measure of the angle formed is one-half the absolute difference of the measures of the intercepted arcs.
Then, you can write and solve this equation:
[tex]x=\dfrac{1}{2}(136\º-28\º)\\\\\\x=54\º[/tex]
