tetalarissa69
tetalarissa69 tetalarissa69
  • 12-03-2020
  • Mathematics
contestada

5+[tex]\sqrt{16x^{2} -37x-2 }=4x[/tex]

solve for me plz with explanation

Respuesta :

surjithayer10 surjithayer10
  • 14-03-2020

Answer:

Step-by-step explanation:

[tex]\sqrt{16x^2-37x-2} =4x-5\\squaring~ both~sides\\16x^2-37x-2=16x^2-40x+25 ~[(a-b)^2=a^2-2ab+b^2]\\16x^2-37x-2-16x^2+40x-25=0\\3x-27=0\\3(x-9)=0\\x-9=0\\x=9[/tex]

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