Answer:
Water would rise in the tank at a rate of 8.45 ft/min
Explanation:
Diameter of leaky cylindrical tank (D) = 1 ft
Base area = πD^2/4 = 3.142×1^2/4 = 0.7855 ft^2
Volumetric flow rate at which water enters the tank = 8 ft^3/min
Volumetric flow rate at which water leaks out = 0.17 × 8 = 1.36 ft^3/min
Volumetric flow rate at which water rises = 8 - 1.36 = 6.64 ft^3/min
Rate at which water would rise in ft/min = volumetric flow rate at which water rises ÷ base area of the cylinder = 6.64 ft^3/min ÷ 0.7855 ft^2 = 8.45 ft/min
