Answer:0.67molL-1
Explanation:
From n= CV
n=2 moles, v=3L
Molarity is given in moles per litre
C= n/v= 2/3=0.67molL-1
Answer:
The molarity of this solution of hydrochloric acid is 0.67 M
Explanation:
Step 1: Data given
Number of moles HCl = 2
Volume = 3.0 L
Molarity = mol / volume
Step 2: Calculate molarity of the solution
Molarity = moles / volume
Molarity HCl solution = 2.0 moles / 3.0 L
Molarity HCl solution = 0.67 M
The molarity of this solution of hydrochloric acid is 0.67 M
