Answer:
141.42 km/h
Explanation:
Since this is a 100km/h right angle crosswind, the speed vector with respect to the ground is the vector speed of the airplane with respect to air + the vector speed of the cross-wind with respect to the ground
<100,0> + <0,100> = <100,100>
This vector has a magnitude of
[tex]v = \sqrt{v_1^2 + v_2^2} = \sqrt{100^2 + 100^2} = \sqrt{10000 + 10000} = \sqrt{20000} = 141.42[/tex] km/h
