Answer:
Verified
Step-by-step explanation:
Let A matrix be in the form of
[tex]\left[\begin{array}{cc}a&b\\c&d\end{array}\right][/tex]
Then det(A) = ad - bc
Matrix A transposed would be in the form of:
[tex]\left[\begin{array}{cc}a&c\\b&d\end{array}\right][/tex]
Where we can also calculate its determinant:
det(AT) = ad - bc = det(A)
So the determinant of the nxn matrix is the same as its transposed version for 2x2 matrices
