Answer:
[tex]\large\boxed{\sqrt{70}\approx8}[/tex]
Step-by-step explanation:
[tex]\text{We know:}\\\\\sqrt{a}=b\iff a^2=b,\ \text{for}\ a\geq0\ \wedge\ b\geq0\\\\5^2=25<70\\6^2=36<70\\7^2=49<70\\8^2=64<70\\9^2=81>70\\\\\text{Therefore}\ \sqrt{64}<\sqrt{70}<\sqrt{81}\Rightarrow8<\sqrt{70}<9.\\\\81-70=11\\70-64=6\\\\6<11\\\\\text{Therefore}\ \sqrt{70}\ \text{is nearest to}\ \sqrt{64}=8[/tex]
