Answer:
45 Mpa
Explanation:
The maximum shear stress, [tex]\tau_{max}[/tex]is given by
[tex]\tau_{max}=\frac {16T}{\pi d^{3}}[/tex]
Where T is the torque and d is the diameter.
Substituting 29820.586 N.m for T and 0.15m for d then we obtain
[tex]\tau_{max}=\frac {16\times 29820.586}{\pi \times 0.15^{3}}=44999999.22\approx 45 Mpa[/tex]
