Answer:
(A) Th = 818.6 K
(B) Qh = 14211.7 J
Explanation:
efficiency (n) = 0.537
temperature of cold reservoir (Tc) = 379 K
heat rejected (Qc) = 6580 J
(A) find the temperature of the hot reservoir (Th)
n = 1 - [tex]\frac{Tc}{Th}[/tex]
0.537 = 1 - [tex]\frac{379}{Th}[/tex]
[tex]\frac{379}{Th}[/tex] = 1 - 0.537 = 0.463
Th = [tex]\frac{379}{0.463}[/tex]
Th = 818.6 K
(B) what amount of heat is put into the engine (Qh) ?
from [tex]\frac{Tc}{Th} = \frac{Qc}{Qh}[/tex]
Qh = 6580 ÷ [tex]\frac{379}{818.6}[/tex]
Qh = 14211.7 J
