Answer:
Option A
0.16
Step-by-step explanation:
Specific gravity, [tex]SG=\frac {M_o}{M_w}[/tex] where M is mass of the object and v is mass of water with same volume as object. Since it's a ratio of masses, it's unitless
Taking density of water as 1 g/ml therefore the volume displaced of 50 ml is equivalent to 50 ml*1g/ml=50 g
Substituting 8 g for [tex]M_o[/tex] and 50 ml for [tex]M_w[/tex] we obtain
[tex]SG=\frac {8g}{50g}=0.16[/tex]
