Answer:
B) No Unique Solutions
Step-by-step explanation:
Given:
[tex]z=x+5y-14[/tex]
[tex]-2y=-4\\y={-4}{-2}=2[/tex]
[tex]3x+y-3z=14[/tex]
now we now the value of y = 2 so we will substitute in equation [tex]z=x+5y-14[/tex]
[tex]z=x+5\times2-14\\z=x+10-14\\z= x-4[/tex]
Now, We have value of y=2 and value of [tex]z=x-4[/tex] Substituting in both the value in equation [tex]3x+y-3z=14[/tex]
[tex]3x+2-3(x-4)=14\\3x+2-3x+12=14\\14=14[/tex]
which means that the equation has Infinite solutions.
