Answer:
The spring constant is [tex]7.89\times10^{-2}\ N/m[/tex]
Explanation:
Given that,
Mass of spider = 2.0 g
Period of oscillation = 1.0 sec
We need to calculate the spring constant
Using formula for simple harmonic oscillator
[tex]T=2\pi\sqrt{\dfrac{m}{k}}[/tex]
[tex]k=((2\pi)^2)\dfrac{m}{T}[/tex]
Where,
m = mass
T = time period
Put the value into the formula
[tex]k=(2\pi)^2\times\dfrac{2.0\times10^{-3}}{1.0}[/tex]
[tex]k=0.0789\ N/m[/tex]
[tex]k=7.89\times10^{-2}\ N/m[/tex]
Hence, The spring constant is [tex]7.89\times10^{-2}\ N/m[/tex]
