Respuesta :

nkirotedoreen46

Answer:

¹⁷⁴₇₇Ir → ¹⁷⁰₇₅Re + ⁴₂He

Explanation:

  • When a radioisotope undergoes alpha decay its mass number decreases by four while its atomic number decreases by 2.
  • The mass number of Iridium is 174
  • Iridium has an atomic number 77
  • Therefore, the decay equation will be;

¹⁷⁴₇₇Ir → ¹⁷⁰₇₅Re + ⁴₂He

  • Iridium-174 undergoes alpha decay to form rhenium-170 which has a mass number of 170 and an atomic number 75.

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