Answer:
sin³x
Step-by-step explanation:
Using the trigonometric identities
1 + cot²x = csc²x
cscx = [tex]\frac{1}{sinx}[/tex]
Given
[tex]\frac{sinx}{1+cot^2x}[/tex]
= [tex]\frac{sinx}{csc^2x}[/tex]
= [tex]\frac{sinx}{\frac{1}{sin^2x} }[/tex]
= sinx × sin²x
= sin³x
