Answer:
[tex]|A|=\sqrt{1^2+(-2)^2+(3)^2}=3.74[/tex]
Explanation:
Given that,
Vector [tex]A=i-2j+3k[/tex]............(1)
We need to find the magnitude of vector A. Let us suppose vector in the form of, R = xi + yj + zk. Its magnitude is given by :
[tex]|R|=\sqrt{x^2+y^2+z^2}[/tex]
In equation (1),
x = 1
y = -2
z = 3
So, the magnitude of vector A is given by :
[tex]|A|=\sqrt{1^2+(-2)^2+(3)^2}[/tex]
|A| = 3.74
So, the magnitude of given vector is 3.74. Hence, this is the required solution.
