Answer:
x=0 and x = -2
Step-by-step explanation:
So we know that a^2 + 2ab + b^2 = (a+b)^2 so, in this situation, we got:
x^2 + 2x + 2 = 0
x^2 + 2x + (1/2*2)^2 +1 = 0
x^2 + 2x + 1^2 + 1 = 0
(x+1)^2 + 1 = 0
(x+1)^2 + 1^2 = 0
We also learn that a^2 + b^2 = (a+b) * (a-b), so in this case:
(x+1)^2 + 1^2 = 0
(x+1+1) * (x+1-1) = 0
(x+2) * (x+0) = 0
x(x+2) = 0
So, there would be 2 result for x now:
x = 0 and x+2 =0
x=0 and x = -2
Hope this help you :3
