Answer:
(4+1)(4^2 - 4*1+1)
(16+1)(16^2-16+1)
Step-by-step explanation:
Sum of cubes is a common case of factorization:
[tex]x^{3}+y^{3}=(x+y)(x^{2} -xy+y^{2} )[/tex]
The first case can be written as: (2^2)^3+1^3= 4^3 + 1^3 which can be factorized as (4+1)(4^2 - 4*1+1)
And we can solve it, and the result is 65.
The second case can be written as (2^4)^3 + 1^3= (16^3 +1^3) which can be factorized as (16+1)(16^2-16+1)=(17)*(241)=4097
