Respuesta :
For every [tex]n \geq 2[/tex], we have
[tex]4.594\log(n)-0.8129>1[/tex]
So, negletting the first term, each term of the sum is greater than 1, which implies
[tex]\displaystyle \sum_{n=2}^\infty 4.594\log(n)-0.8129> \sum_{n=1}^\infty 1 =\infty[/tex]
Which means that the series diverges.
Answer:
The series diverges.
Step-by-step explanation:
Apply the limit test: The Limit of 4.594 ln(n)- 0.8129 as n ---> ∞ is ∞ (not equal to 0) , so the series diverges.
