Answer:
4.08 x 10⁻¹⁵ m
Explanation:
r₀ = constant of proportionality = 1.3 x 10⁻¹⁵ m
r = radius of the nucleus 31P = ?
A = mass number of the nucleus 31P = 31
Radius of the nucleus is given as
[tex]r=r_{o}A^{\frac{1}{3}}[/tex]
Inserting the values
[tex]r=(1.3\times 10^{-15})(31)^{\frac{1}{3}}[/tex]
[tex]r=(1.3\times 10^{-15})(3.14)[/tex]
r = 4.08 x 10⁻¹⁵ m
