Answer:
Frequency, f = 0.274 Hz
Explanation:
It is given that,
Mass of the girl, m = 40 kg
Length of the rope, L = 3.3 m
We need to find the frequency of her swinging. It is an example of simple harmonic motion whose time period is given by :
[tex]T=2\pi\sqrt{\dfrac{L}{g}}[/tex]
[tex]T=2\pi\sqrt{\dfrac{3.3\ m}{9.8\ m/s^2}}[/tex]
T = 3.64 seconds
The frequency, [tex]f=\dfrac{1}{T}[/tex]
[tex]f=\dfrac{1}{3.64\ s}[/tex]
f = 0.274 Hz
So, the frequency of her swinging is 0.274 Hz. Hence, this is the required solution.
