Answer:
[tex]\large\boxed{f^{-1}(x)=\dfrac{3x+51}{2}=\dfrac{3}{2}x+\dfrac{51}{2}}[/tex]
Step-by-step explanation:
[tex]f(x)=\dfrac{2x}{3}-17\to y=\dfrac{2x}{3}-17\\\\\text{exchange x to y and vice versa:}\\\\x=\dfrac{2y}{3}-17\\\\\text{solve fro y:}\\\\\dfrac{2y}{3}-17=x\qquad\text{add 17 to both sides}\\\\\dfrac{2y}{3}=x+17\qquad\text{multiply both sides by 3}\\\\2y=3x+51\qquad\text{divide both sides by 2}\\\\y=\dfrac{3x+51}{2}=\dfrac{3}{2}x+\dfrac{51}{2}[/tex]
