Answer:
x = 30t cos 20 or x = 28.19t.
y = 30t sin 20 - 4.9t^2 + 2 or y = -4.9t^2 + 10.26t + 2.
Step-by-step explanation:
The horizontal component of the velocity = 30 cos 20 m/s so the distance at time t seconds = 30t cos 20.
The vertical component is obtained from the equation of motion
s = ut - 1/2* 9.8t^2 + 2
u = 30 sin 20
Vertical component = 30t sin 20 - 4.9t^2 + 2.
