Answer:
[tex]-\frac{13\sqrt{x} }{x}[/tex]
Step-by-step explanation:
We have been given the following expression;
-13/√x
In order to rationalize the denominator, we multiply the numerator and the denominator by √x;
[tex]-\frac{13}{\sqrt{x}}=-\frac{13\sqrt{x} }{\sqrt{x}\sqrt{x}}\\ \\-\frac{13\sqrt{x} }{\sqrt{x^{2} } }\\\\-\frac{13\sqrt{x} }{x}[/tex]
