jetblackcap jetblackcap
  • 11-05-2019
  • Mathematics
contestada

Pls help me...........

Pls help me class=

Respuesta :

jimrgrant1 jimrgrant1
  • 11-05-2019

Answer:

[tex]\frac{4}{5}[/tex]

Step-by-step explanation:

Using the Pythagorean identity

sin²x + cos²x = 1, then

sin²x = 1 - cos²x

sinx = [tex]\sqrt{1-cos^2x}[/tex]

note that cosΘ = [tex]\frac{6}{10}[/tex] = [tex]\frac{3}{5}[/tex]

sinΘ = [tex]\sqrt{1-(3/5)^2}[/tex]

        = [tex]\sqrt{1-\frac{9}{25} }[/tex]

        = [tex]\sqrt{\frac{16}{25} }[/tex] = [tex]\frac{4}{5}[/tex]

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