For this case we must find the product of the following expressions:
[tex]\frac {3x} {x + 1} * \frac {x} {x-7}[/tex]
So:
[tex]\frac {3x ^ 2} {x ^ 2-7x + x-7} =\\\frac {3x ^ 2} {x ^ 2-6x-7}[/tex]
So, we have to:
[tex]\frac {3x} {x + 1} * \frac {x} {x-7} = \frac {3x ^ 2} {x ^ 2-6x-7}[/tex]
Answer:
[tex]\frac {3x ^ 2} {x ^ 2-6x-7}[/tex]
Option C
