Answer:
The perimeter of the square is [tex]4\ in[/tex]
Step-by-step explanation:
Let
x----> the length side of the square
we know that
In an isosceles right triangle the measures of the internal angles are 45°-90°-45°
so
the horizontal distance is equal to the vertical distance
[tex]2=x+x[/tex]
[tex]x=1\ in[/tex]
The perimeter of the square is
[tex]P=4b[/tex]
we have
[tex]b=1\ in[/tex]
substitute
[tex]P=4(1)=4\ in[/tex]
