Answer: [tex]\bold{c)\quad \dfrac{11+7i}{5}}[/tex]
Step-by-step explanation:
[tex]\dfrac{3+i}{2-i}\cdot\dfrac{4+i}{2+i}\\\\\\\text{Multiply using any method:}\\=\dfrac{12+7i+i^2}{4+2i-2i-i^2}\\\\\\\text{Add like terms and replace }i^2\ \text{with -1}\\=\dfrac{12+7i+(-1)}{4-(-1)}\\\\\\=\large\boxed{\dfrac{11+7i}{5}}[/tex]
