Answer:
[tex]\large\boxed{(3x+5)(2x^2-3x+2)=6x^3+x^2-9x+10}[/tex]
Step-by-step explanation:
[tex]\text{Use FOIL:}\ (a+b)(c+d)=ac+ad+bc+bd\\\\(3x+5)(2x^2-3x+2)\\\\=(3x)(2x^2)+(3x)(-3x)+(3x)(2)+(5)(2x^2)+(5)(-3x)+(5)(2)\\\\=6x^3-9x^2+6x+10x^2-15x+10\\\\\text{combine like terms}\\\\=6x^3+(-9x^2+10x^2)+(6x-15x)+10\\\\=6x^3+x^2-9x+10[/tex]
