Respuesta :

[tex]\bf \textit{volum of a pyramid}\\\\ V=\cfrac{1}{3}Bh~~ \begin{cases} B=area~of\\ \qquad its~base\\ h=height\\[-0.5em] \hrulefill\\ B=\stackrel{18\times 18}{324}\\ h=12 \end{cases}\implies V=\cfrac{1}{3}(324)(12)\implies V=1296[/tex]

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