lyyeol60
lyyeol60 lyyeol60
  • 15-02-2019
  • Mathematics
contestada

Prove that 2017(2018^9+2018^8+…+2018^2+2019+1)=2018^10+2017

Respuesta :

5naka
5naka 5naka
  • 15-02-2019
let a=2018, we can rewrite the question into

[tex](a-1)(a^9+a^8+...+a^2+a+2)\\=(a-1)(a^9+a^8+...+a^2+a+1)+(a-1)\\=a^{10}-1+a-1[/tex]

substitute back a = 2018, obtained

[tex] {2018}^{10} + 2016[/tex]
well, there is something wrong here
Answer Link
UncleCeyth
UncleCeyth UncleCeyth
  • 21-11-2019

Answer:

2016

Step-by-step explanation:

Answer Link

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