Answer:
see explanation
Step-by-step explanation:
Using the laws of logarithms
• log x + log y ⇔ log(xy)
• log x - log y ⇔ log ([tex]\frac{x}{y}[/tex])
• log [tex]x^{n}[/tex] ⇔ nlog x
Hence
2 [tex]log_{3}[/tex] x + [tex]log_{3}[/tex] 2x - [tex]log_{3}[/tex](x - 3)
= [tex]log_{3}[/tex] x² + [tex]log_{3}[/tex] 2x - [tex]log_{3}[/tex](x - 3)
= [tex]log_{3}[/tex] 2x³ - [tex]log_{3}[/tex](x - 3)
= [tex]log_{3}[/tex]([tex]\frac{2x^3}{x-3}[/tex])
