mickecia1
mickecia1 mickecia1
  • 12-02-2019
  • Mathematics
contestada

n-[tex]\frac{2n-3}{9}[/tex]+2=[tex]\frac{2n+1}{3}[/tex]

Solve

Respuesta :

Panoyin
Panoyin Panoyin
  • 12-02-2019

Answer:[tex]n = -12[/tex]

Step-by-step explanation:[tex]n - \frac{2n - 3}{9} + 2 = \frac{2n + 1}{3}[/tex]

[tex]\frac{9n - 2n - 3 + 18}{9} = \frac{2n +  1}{3}[/tex]

[tex]\frac{7n + 15}{9} = \frac{2n + 1}{3}[/tex]

[tex]9(2n + 1) = 3(7n + 15)[/tex]

[tex]18n + 9 = 21n + 45[/tex]

[tex]9 = 3n + 45[/tex]

[tex]-36 = 3n[/tex]

[tex]-12 = n[/tex]

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